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Q.
What is the below pseudo code trying to do, where pt is a node pointer and root pointer.

redblack(Node root, Node pt) :
    if (root == NULL)
       return pt
 
    if (pt.data < root.data)
    {
        root.left  =   redblack(root.left, pt);
        root.left.parent = root
    }
    else if (pt.data > root.data)
    {
        root.right = redblackt(root.right, pt)
        root.right.parent = root
    }
   return root

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1.
Select the code snippet which performs in-order traversal.

a)

public void inorder(Tree root)
{
 System.out.println(root.data);
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}

b)

public void inorder(Tree root)
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 inorder(root.left);
 System.out.println(root.data);
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}

c)

public void inorder(Tree root)
{
 System.out.println(root.data);
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 inorder(root.left);
}

d) None of the mentioned
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Why Red-black trees are preferred over hash tables though hash tables have constant time complexity?
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Which of the following is an application of Red-black trees and why?
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