Consider the following C declaration
struct {
short s[5];
union {
float y;
long z;
}u;
}t;
Assume that objects of type short, float and long occupy 2 bytes, 4 bytes and 8 bytes, respectively. The memory requirement for variable t, ignoring alignment considerations, is
The correct answer is "option 2"
CONCEPT:
Structure in C is a user-defined data type that is used to store the collection of different data types.
The total size of the structure is the sum of the size of every data member.
Union is a user-defined data type that is used to store different data types in the same memory location.
The total size of the union is the size of the largest data member.
EXPLANATION:
Given the size of short, float and long is 2 bytes, 4 bytes, and 8 bytes, respectively.
Therefore,
Size of Structure → size of ( short s[5] ) + size of Union
Here, Size of Union = 8 bytes { largest data member is long }.
Size of short s[5] → 2×5 → 10 bytes
Size of Structure → 10+8 →18 bytes.
Hence, the correct answer is "option 2".
